Question : Générateur de mot de passe complexe et définissable en java
import java.security.SecureRandom; import java.util.Scanner; public class PasswordGenerator { private static final String UPPER = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; private static final String LOWER = "abcdefghijklmnopqrstuvwxyz"; private static final String DIGITS = "0123456789"; private static final String PUNCTUATION = "!@#$%&*()_+-=[]|,./?><"; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); SecureRandom random = new SecureRandom(); System.out.println("Entrez la longueur du mot de passe:"); int length = scanner.nextInt(); System.out.println("Inclure des caractères majuscules? (o/n)"); boolean includeUpper = scanner.next().equalsIgnoreCase("o"); System.out.println("Inclure des caractères minuscules? (o/n)"); boolean includeLower = scanner.next().equalsIgnoreCase("o"); System.out.println("Inclure des chiffres? (o/n)"); boolean includeDigits = scanner.next().equalsIgnoreCase("o"); System.out.println("Inclure des caractères de ponctuation? (o/n)"); boolean includePunctuation = scanner.next().equalsIgnoreCase("o"); String characters = ""; if (includeUpper) { characters += UPPER; } if (includeLower) { characters += LOWER; } if (includeDigits) { characters += DIGITS; } if (includePunctuation) { characters += PUNCTUATION; } char[] password = new char[length]; for (int i = 0; i < length; i++) { password[i] = characters.charAt(random.nextInt(characters.length())); } System.out